Constant hazard fitted to early follow-up of a bathtub-hazard cohort

Fits an exponential model to follow-up that covers only the early part of a bathtub hazard. The fitted hazard is the deaths divided by the person-years at risk, the rate formula of the Adverse Event Rate page (HE-FM-AER-002), and the exponential model then implies survival exp(-lambda_hat t) and mean survival 1 divided by lambda_hat. Comparing these with the bathtub values shows how a constant hazard misplaces deaths and overstates the tail.

Signature

lambda_hat = D / PY; S_t = exp(-lambda_hat * t); E_T = 1 / lambda_hat
Inputs
InputsDefinitionUnit
DDeaths during follow-up per person entering, equal to 1 minus survival at the end of follow-up when no one is censored earlierdeaths per person entering
PYPerson-years lived during follow-up per person enteringyears
tTime since the procedure at which survival under the fitted constant hazard is readyears
Output
lambda_hatConstant hazard of the exponential model fitted to the follow-up periodevents per person-year
S_tProportion alive at time t under the fitted exponential modelproportion of the starting cohort
E_TMean survival under the fitted exponential model, extrapolated for lifeyears

Function

Survival and mean survival from a bathtub-shaped hazard

Maps a hazard that is high soon after a procedure, falls to a stable level and later rises with age to the survival curve and the mean survival that a health economic model needs. Survival at time t is the exponential of minus the cumulative hazard up to t, and mean survival is the area under the survival curve. The formulae below apply this to a piecewise-constant hazard schedule, to a constant hazard fitted to early follow-up, to a sum of two Weibull hazards and to an all-cause hazard built from background and excess components. Turning an interval hazard into a cycle transition probability uses the conversion already given on the Transition Probability page (HE-FM-TP-001), which is not repeated here.

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Implementations

  • Excel

    Exponential fit to bathtub follow-up in three cells

    With named cells Deaths, PersonYears and Time, the first formula returns the fitted hazard in a cell named FittedHazard, and the other two return survival at Time and the implied mean survival.

    =Deaths/PersonYears; =EXP(-FittedHazard*Time); =1/FittedHazard

Assumptions

  • Complete follow-up to the end of the bathtub trial period

    Every patient is followed to the end of the follow-up period or to death, so D and PY are complete. With censoring, D is the number of observed deaths and PY the total observed time at risk.

  • Exponential model applied to a non-constant hazard

    The formula is the correct fit of a constant hazard, but the bathtub cohort does not have one. The fitted hazard is the person-time weighted average of the hazards seen during follow-up and says nothing about the hazard after it.

Worked examples

  • Five-year exponential fit and five-year survival

    In the article's example, 0.286448 of the cohort die within five years over 4.063613 person-years, giving a fitted hazard of about 0.070491 per year. Five-year survival under the fit is 0.7030 against 0.7136 under the bathtub hazard, and the implied mean survival is 14.1862 years, the article's 14.19.

    D = 0.286448; PY = 4.063613; t = 5; lambda_hat = 0.070491; S_t = 0.7030; E_T = 14.1862
  • Three-month survival under the five-year exponential fit

    The same fit predicts three-month survival of 0.9825, against 0.9048 under the bathtub hazard, so it places far too few deaths in the post-procedure period.

    D = 0.286448; PY = 4.063613; t = 0.25; lambda_hat = 0.070491; S_t = 0.9825; E_T = 14.1862

Common errors

  • Accepting a constant hazard because five-year survival matches

    A fit that matches the Kaplan-Meier curve at the end of follow-up can still misplace deaths and the tail. In the article's example the exponential gives five-year survival of 0.7030 against 0.7136, yet overstates mean survival by 3.61 life-years (14.19 against 10.58), most of it after year fifteen.

Sources

  • Exponential model with a constant hazard in DSU TSD 14

    Latimer N. NICE DSU Technical Support Document 14: Survival analysis for economic evaluations alongside clinical trials, extrapolation with patient-level data. Sheffield: Decision Support Unit, ScHARR, University of Sheffield; 2011, last updated March 2013. Section 2.1, which gives the exponential distribution a constant hazard lambda and survivor function exp(-lambda t), and section 2, which equates mean survival with the area under the survival curve.

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  • Event rate as events divided by time at risk for a bathtub fit

    Gidwani R, Russell LB. Estimating transition probabilities from published evidence: a tutorial for decision modelers. PharmacoEconomics. 2020;38(11):1153-1164. Section on converting to the cycle length, which defines a rate as the number of events divided by the total time at risk.

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Canonical Identity

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